Trapez Seiten Winkel berechen?

1 Antwort

Vom Fragesteller als hilfreich ausgezeichnet

Berechnung
α1 = ARCCOS( (b² - e² - a²) / (-2 * e * a) )
α1 = ARCCOS( (22^2 - 38^2 - 49^2) / (-2 * 38 * 49) )
α1 = 25,508133°
---
β = ARCCOS( (e² - b² - a²) / (-2 * b * a) )
β = ARCCOS( (38^2 - 22^2 - 49^2) / (-2 * 22 * 49) )
β = 48,058819°
---
γ1 = 180 - α1 - β
γ1 = 180 - 25,508133 - 48,058819
γ1 = 106,433048°
---
h = a * SIN(β)
h = 22 * SIN(48,058819)
h = 16,36429 mm
---
a1 = h * tan(α3)
a1 = 16,36429 * tan(50)
a1 =19,502201 mm
---
a2 = Wurzel(b² - h²)
a2 = Wurzel(22^2 -16,36429^2 )
a2 = 14,7040815 mm
---
c = a - a1 - a2
c = 49 - 19,502201 - 14,7040815
c = 14,793717 mm
---
d = h / sin(α)
d = 16,36429 / sin(40)
d = 25,458316 mm
---

α2 = α - α1
α2 = 40 - 25,508133
α2 = 14,491867°
---
a3 = a2 + c
a3 = 14,704082 + 14,793717
a3 = 29,497799 mm
---
f = Wurzel(a3² + h²)
f = Wurzel(29,497799^2 + 16,36429^2)
f = 33,732923 mm
---
A = ((a + c) / 2) * h
A = ((49 + 14,793717) / 2) * 16,36429
A = 521,969443 mm²

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 - (Mathematik, rechnen, Gleichungen)