Antwort
f(x)=0 0= x² -4x-5
x1/2= -p/2±√((p/2)^2-q)
p= -4 q=-5 x1/2= 4/2±√((-4/2)^2-(-5))
x1/2= 2±√9
x1= 2+3= 5 x2= 2-3= -1
f(x)=0 0= x² -4x-5
x1/2= -p/2±√((p/2)^2-q)
p= -4 q=-5 x1/2= 4/2±√((-4/2)^2-(-5))
x1/2= 2±√9
x1= 2+3= 5 x2= 2-3= -1